Ch 02 Quiz 6

1. (cm) Given a list of letters and a list of words, total of 1 for each element in the first list that appears in somewhere the corresponding word from the second list.

    cm ['a','p','e','s'] ["apple","grade","reach","bonus"] == 3
   

   Explanation I:

   The letter 'a' corresponds to the word "apple", so contributes one to the total. The letter 'p' does not appear in the corresponding word "grade", contributes zero to the total.

   Explanation II:

   Letter	Word	Contribution
   a	apple	1
   p	grade	0
   e	leech	1
   s	bonus	1

   The final result is 1 + 0 + 1 + 1 = 3.

2. (rmake) Given a list of strings (“colors”) and a list of strings (“modes”), produce a list of strings of the form (rectangle 100 20 MODE COLOR).

    rmake ["orange","blue"] ["outline","solid"]
     == ["(rectangle 100 20 outline orange)",
         "(rectangle 100 20 solid ornage)",
         "(rectangle 100 20 outline blue)",
         "(rectangle 100 20 solid blue)"]
   

3. (s20) Given a list of Int, produce the shortest sub-list you can, starting at the beginning and ending as soon as the total is above 20. If the total is never above 20, the result is the whole list.

    s20 [1,2,3] == [1,2,3]
    s20 [1,2,3,10,7,13,14,15] == [1,2,3,10,7]
    s20 [0,20,1,2,3] == [0,20,1]
   

   Explanation: In the second example, 1+2+3+10 = 16, but adding the next number gives 16+7=23. In the third example, 0+20 is not above 20, so it takes one more number.